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P10 · 4.10Paper 2🔶 Yr11 — new

Force & Motion

Newton's laws, F=ma, terminal velocity, stopping distances, momentum. Key Year 11 topic — heavily examined.

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Key facts

Newton's Laws

  • 1st Law: an object remains at rest or constant velocity unless a resultant force acts on it.
  • 2nd Law: F = ma (resultant force = mass × acceleration). Units: F in N, m in kg, a in m/s².
  • 3rd Law: for every action there is an equal and opposite reaction (forces act on different objects).
  • Inertia = tendency to resist changes in motion. More mass = more inertia.
  • Inertial mass = F/a (resistance to acceleration).

Terminal velocity

  • Falling object: weight (down) vs air resistance (up).
  • Initially: weight > air resistance → accelerates downward.
  • As speed increases: air resistance increases.
  • Terminal velocity: weight = air resistance → resultant = 0 → constant velocity.
  • On VT graph: curve that levels off horizontally at terminal velocity.

Stopping distances

  • Thinking distance = distance travelled during reaction time (before brakes applied).
  • Affected by: speed, tiredness, alcohol, drugs, distractions.
  • Braking distance = distance to stop after brakes applied.
  • Affected by: speed (large effect — v²), road condition, tyre condition, brake condition, mass.
  • Total stopping distance = thinking distance + braking distance.

Momentum

  • Momentum = mass × velocity (p = mv). Unit: kg m/s. Vector quantity.
  • Conservation of momentum — total momentum before collision = total momentum after (in a closed system).
  • Impulse = force × time = change in momentum (Ft = Δmv).
  • Larger collision time → smaller force for same change in momentum (crumple zones, air bags).
Exam questions — 4 questions · 12 marks
⚡ Extended questions included. Show all working for calculation questions. The AI marks against the real AQA mark scheme.
1 markTerminal velocityAQA 8463 P2 style

A skydiver jumps from a plane. Initially they accelerate. Eventually they reach terminal velocity. Explain why they stop accelerating.

A They run out of gravitational potential energy
B The air resistance force increases until it equals the weight — the resultant force becomes zero so acceleration stops
C Their mass increases as they fall through denser air
D The gravitational force decreases as they move closer to the ground
4 marksF=ma calculationAQA 8463 P2 style

A car of mass 1500 kg accelerates from 0 to 30 m/s in 10 seconds. Calculate (a) the acceleration and (b) the resultant force required. (4 marks)

Hint: (a) a = Δv/t. (b) F = ma. Show both steps clearly.
+40 XP
4 marksMomentum conservationAQA 8463 P2 Higher style

A 2000 kg car moving at 15 m/s collides with a stationary 1000 kg car. They stick together. Calculate their velocity after the collision. (3 marks)

Hint: Total momentum before = total momentum after. The cars stick together so use combined mass after.
+40 XP
1 markStopping distance factorAQA 8463 P2 style

A driver doubles their speed from 20 m/s to 40 m/s. Assuming the same braking force, what happens to the braking distance?

A It doubles
B It quadruples
C It stays the same
D It increases by 1.5 times

Module complete! 🎉

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