Scalar vs vector quantities, resolving forces, vector addition, free body diagrams.
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CognitoScalars and vectors
Key facts & equations
Scalars and vectors — fill in the table
Quantity type
Definition
Examples
Scalar
Vector
When adding vectors, direction matters — two 3 N forces can give 0 N (opposite) to 6 N (same direction). Free body diagrams show all forces acting on an object as arrows from the object: arrow length represents force magnitude, arrow direction shows force direction.
Resultant forces and equilibrium
Resultant force: the single force that has the same effect as all forces acting together.
Add forces in the same direction. Subtract opposing forces.
If resultant = 0 → object in equilibrium (stationary or constant velocity).
Scale drawing: draw forces tip-to-tail → resultant is the closing vector.
Pythagoras: for two perpendicular forces. F_resultant = √(F1² + F2²).
Resolving forces (Higher)
Any force can be split into horizontal and vertical components.
Horizontal component: F_h = F cos θ.
Vertical component: F_v = F sin θ.
Useful for inclined planes: weight component along slope = mg sin θ.
Weight component perpendicular to slope = mg cos θ.
Contact and non-contact forces — fill in the table
Force type
How it acts
Examples
Contact forces
Non-contact forces
Forces always come in interaction pairs (Newton's 3rd law). Gravity is always attractive; electrostatic and magnetic forces can attract or repel.
A boat experiences: engine thrust = 1200 N forward, water resistance = 450 N backward, wind force = 300 N forward. Calculate the resultant force and state the direction. (2 marks)
Hint: Add all forces in the same direction first. Then find the difference between forward and backward totals.
+30 XP
1 markEquilibrium conditionAQA 8463 style
An object moves at constant velocity. Which statement must be true?
A boat is pushed by an engine with force 60 N East and a current with force 80 N North. Calculate the magnitude and direction of the resultant force. (3 marks)
Hint: Perpendicular forces: use Pythagoras. Magnitude = √(60² + 80²). Direction: tan θ = opposite/adjacent.