Session XP: 0
P8 ยท 4.8Paper 2๐Ÿ”ถ Yr11 โ€” new

Forces in Balance

Vectors, scalars, resultant forces, moments, centre of mass. Year 11 content โ€” new for Ander.

โ€”
Best score
โ€”
Last attempt
Best attempt progress
0
XP earned
Watch first
โ–ถ
MyGCSEScience ยท AQA Physics
Forces in Balance โ€” watch on MyGCSEScience
โ†—
FreeScienceLessons ยท AQA PhysicsForces in Balance
Cognito ยท AQA Physics 2026/27Resultant Forces and Moments
Key facts

Vectors and scalars

  • Scalar โ€” has magnitude only. Examples: speed, distance, mass, temperature, energy.
  • Vector โ€” has magnitude AND direction. Examples: velocity, displacement, force, acceleration, momentum.
  • Vectors are drawn as arrows โ€” length represents magnitude, arrow shows direction.
  • Resultant force โ€” the single force that has the same effect as all forces acting combined.
  • Balanced forces (resultant = 0) โ†’ object moves at constant velocity or stays still.
  • Unbalanced forces (resultant โ‰  0) โ†’ object accelerates in direction of resultant.

Moments and centre of mass

  • Moment = Force ร— perpendicular distance from pivot. Unit: Nm.
  • Clockwise moments = anticlockwise moments for a balanced object (principle of moments).
  • Centre of mass โ€” the point where the weight of an object appears to act.
  • Suspended objects come to rest with their centre of mass directly below the pivot.
  • Objects topple when their centre of mass moves outside the base โ€” wide base and low CoM = more stable.
Exam questions โ€” 4 questions ยท 12 marks
โšก Extended questions included. Show all working for calculation questions. The AI marks against the real AQA mark scheme.
1 markVector vs scalarAQA 8463 P2 style

Which pair of quantities are both vectors?

A Speed and velocity
B Force and acceleration
C Mass and weight
D Distance and displacement
3 marksResultant forceAQA 8463 P2 style

A car of mass 1200 kg has a driving force of 3000 N forwards and a friction force of 800 N backwards. Calculate (a) the resultant force and (b) the acceleration of the car. (3 marks)

Hint: (a) Subtract opposing forces. (b) Use F = ma, rearranged as a = F/m.
+30 XP
4 marksMoment calculationAQA 8463 P2 style

A 3 m uniform beam is balanced on a pivot at its centre (1.5 m from each end). A 60 N weight hangs 1.5 m to the left of the pivot. Calculate the force F that must be applied 0.5 m to the right of the pivot to balance the beam. (4 marks)

Hint: Moment = force ร— distance from pivot. Set clockwise = anticlockwise moments and solve for F.
+40 XP
1 markCentre of mass stabilityAQA 8463 P2 style

Why is a racing car designed with a very low centre of mass and a wide wheelbase?

A To reduce air resistance and allow higher speeds
B To make the car heavier so it has more grip
C A low centre of mass and wide base means the car can tilt further before the centre of mass moves outside the base โ€” making it much harder to topple
D To reduce the moment of the driving force

Module complete! ๐ŸŽ‰

Score loading...

โšก +10 XP